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## Introduction

Hey it's a me again @drifter1! Today we continue with **Physics** and more specifically the branch "**Classical Mechanics**" to get into the quantity called **Torque**, that's strongly related to Angular Acceleration. So, without further ado, let's get straight into it!

## Torque

Similar to how we define**Force**to be the measure of

*how much*we have to push an object to

*make it move from one point to another*, we also define a quantity for measuring

*how much*we have to push an object

*to make it rotate around its axis*. This quantity is called

**Torque**and labeled by the Greek letter

*τ*. In S.I. it's measured by the Newton-meter (N·m)The axis of rotation, which sometimes is also referred to as

**pivot point**, is mostly labeled using the capital letter

*O*. The Torque that we have to apply for an object to rotate about an axis of rotation

**depends on two things**:

- The
**force**that we apply to make it rotate*F* - The
**distance**from the pivot point up to the point where the force acts, a quantity that is called the*r***moment arm**

We all know that force is a vector quantity, but note that in this case

**the distance r is also a vector**that points from the axis of rotation to the point where the force acts on. So, in the end Torque is defined as the

**vector cross product**between the distance vector r and force F:

In the last part of the equation,

*θ*refers to the

**angle**between vector r and F. The direction of the torque vector can be found easily using a so called

**right hand grip rule**. We just have to curl our hand around the axis of rotation, with the fingers pointing in the direction of the force, then the torque vector points in the direction of the thumb.

So, what's the meaning of Torque? Well, intuitively speaking we all know that opening a door is easier when pushing on the side of the door that is the farthest away from the hinges (where the door handle lies). Pushing on the side closest to them, requires much more force! The actual work done is actually the same in both cases, but I guess we prefer less force over a large distance than large force over a smaller distance.

**Simple Zero-Torque cases**:

- Applying torque at the pivot point (r = 0) causes no torque
- Applying force parallel to the pivot point and so distance vector (θ = 0) causes no torque

## Relation to Angular Acceleration

Thinking about how angular acceleration and tangential acceleration are related to each other by:*a*and Newton's 2nd law states:

_{tan}= ra*F*, we can substitute the first equation into the scond one and get:

_{tan}= m a_{tan}So, the sum of torque for an object is equal to it's moment of inertia

*I*times the angular acceleration

*a*. When the sum of torques Στ equals zero, we say that we are in a

**rotational equilibrium**or that there is

**no net torque on the object**.

Based on that there are

**two types of Torque**:

**Static Torque**: This type of torque does not produce angular acceleration. Think about someone pushing a closed door without it actually opening, or an cyclist driving at a constant speed, still applying force, but just not accelerating!**Dynamic Torque**: This type of torque does produce angular acceleration. So, any case where the acceleration changes. Any case where the net torque is not zero!

Based on Newton's First Law, we can say that objects don't only tend to remain at rest in the meaning of not changing position, but in respect to Angular motion also want to

**keep the "rotational state" that they are in**(spinning about the axis or not).

## Exercise 1 from Khan Academy

Lastly let's also get into a simple example. Consider a wheel where two forces act on it at the left and right side. The first one acts at an angle of θ_{1}= 135° and distance of r

_{1}= 75mm to the axis of rotation and has a known magnitude of F

_{1}= 5N. The second one acts perpendicular to the distance vector (θ

_{2}= 90°) and at a distance of r

_{2}= 100mm with unknown magnitude. What's the magnitude of the second force F

_{2}if we want the wheel to be in a rotational equilibrium?

**Solution**:

For the wheel to be in a rotational equilibrium, the net sum of the two torques must be equal to zero. We have all the needed quantities to calculate the first torque τ

*1*:

So we are defining positive torque in the direction of the first force.

We want τ

_{1}+ τ

_{2}= 0 and so:

Note that the torque that comes from having a positive force (similar direction as F

_{1}) is negative torque, as the two torques make the wheel spin in opposite directions, in the end causing it to just stand still!

## RESOURCES:

### References

- https://www.physics.uoguelph.ca/tutorials/torque/Q.torque.intro.html
- https://www.physics.uoguelph.ca/tutorials/torque/Q.torque.intro.angacc.html
- https://courses.lumenlearning.com/boundless-physics/chapter/torque-and-angular-acceleration/
- https://www.khanacademy.org/science/physics/torque-angular-momentum/torque-tutorial/a/torque

### Images

Mathematical equations used in this article, where made using quicklatex.

## Previous articles of the series

### Rectlinear motion

- Velocity and acceleration in a rectlinear motion -> velocity, acceleration and averages of those
- Rectlinear motion with constant acceleration and free falling -> const acceleration motion and free fall
- Rectlinear motion with variable acceleration and velocity relativity -> integrations to calculate pos and velocity, relative velocity
- Rectlinear motion exercises -> examples and tasks in rectlinear motion

### Plane motion

- Position, velocity and acceleration vectors in a plane motion -> position, velocity and acceleration in plane motion
- Projectile motion as a plane motion -> missile/bullet motion as a plane motion
- Smooth Circular motion -> smooth circular motion theory
- Plane motion exercises -> examples and tasks in plane motions

### Newton's laws and Applications

- Force and Newton's first law -> force, 1st law
- Mass and Newton's second law -> mass, 2nd law
- Newton's 3rd law and mass vs weight -> mass vs weight, 3rd law, friction
- Applying Newton's Laws -> free-body diagram, point equilibrium and 2nd law applications
- Contact forces and friction -> contact force, friction
- Dynamics of Circular motion -> circular motion dynamics, applications
- Object equilibrium and 2nd law application examples -> examples of object equilibrium and 2nd law applications
- Contact force and friction examples -> exercises in force and friction
- Circular dynamic and vertical circle motion examples -> exercises in circular dynamics
- Advanced Newton law examples -> advanced (more difficult) exercises

### Work and Energy

- Work and Kinetic Energy -> Definition of Work, Work by a constant and variable Force, Work and Kinetic Energy, Power, Exercises
- Conservative and Non-Conservative Forces -> Conservation of Energy, Conservative and Non-Conservative Forces and Fields, Calculations and Exercises
- Potential and Mechanical Energy -> Gravitational and Elastic Potential Energy, Conservation of Mechanical Energy, Problem Solving Strategy & Tips
- Force and Potential Energy -> Force as Energy Derivative (1-dim) and Gradient (3-dim)
- Potential Energy Diagrams -> Energy Diagram Interpretation, Steps and Example
- Internal Energy and Work -> Internal Energy, Internal Work

### Momentum and Impulse

- Conservation of Momentum -> Momentum, Conservation of Momentum
- Elastic and Inelastic Collisions -> Collision, Elastic Collision, Inelastic Collision
- Collision Examples -> Various Elastic and Inelastic Collision Examples
- Impulse -> Impulse with Example
- Motion of the Center of Mass -> Center of Mass, Motion analysis with examples
- Explaining the Physics behind Rocket Propulsion -> Required Background, Rocket Propulsion Analysis

### Angular Motion

- Angular motion basics -> Angular position, velocity and acceleration
- Rotation with constant angular acceleration -> Constant angular acceleration, Example
- Rotational Kinetic Energy & Moment of Inertia -> Rotational kinetic energy, Moment of Inertia
- Parallel Axis Theorem -> Parallel axis theorem with example

## Final words | Next up

This is actually it for today's post! Next time we will continue with the rotation around a moving axis....

See ya!

Keep on drifting!